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Q.

When I₂ oxidizes $S_{2} O_{3}^{- 2}$ , the average oxidation number of Sulphur in the product formed is

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a

+6

b

+4

c

+2

d

+2.5

answer is D.

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Detailed Solution

$2 S_{2} O_{3}^{- 2} + I_{2} \to S_{4} O_{6}^{- 2} + 2 I^{-}$

Oxidation state of S = +5,0,0,+5

Average oxidation state = $\frac{5 + 0 + 0 + 5}{4} = 2.5$

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