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When light is incident on a medium at angle $i$ and refracted into a second medium at an angle $r$ , the graph of $\sin i v s \sin r$ is as shown in the graph. From this, one can conclude that

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velocity of light in the second medium is 1.73 times the velocity of light in the I medium

velocity of light in the I medium is 1.73 times the velocity in the II medium

the critical angle for the two media is given by $\sin i_{c} = \frac{1}{\sqrt{3}}$

$\sin i_{c} = \frac{1}{2}$

answer is B, C.

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Detailed Solution

We can write,

$\frac{v_{1}}{v_{2}} = \frac{\sin i}{\sin r} = c o t 30^{\circ} = \sqrt{3} = 1.732 .$

Critical angle, $\sin C = \frac{1}{μ} = \frac{1}{\sqrt{3}}$

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