When Lithium vapor is taken in a discharge tube and the potential difference between the electrodes is 5.4 eV, there is a sudden increase in the flow of current. The ionization energy of Lithium is

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54eV

$520 KJ {mol}^{- 1}$

$54 KJ {atoms}^{- 1}$

$5.4 eV {atom}^{- 1}$

answer is B, D.

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Detailed Solution

Ionization energy of lithium, Li is equal to the potential difference between the electrodes. Hence, if we supply more than 5.4 eV through electrodes then suddenly increase the flow of current is observed by loosing electrons.

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