When Manganese dioxide is heated with aluminum powder , the products obtained are

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$Mn, {Al}_{2} O_{3}$ and heat

$MnO$ and ${Al}_{2} O_{3}$

$MnO, {Al}_{2} O_{3}$ and heat

$Mn$ and ${Al}_{2} O_{3}$

answer is A.

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Detailed Solution

On heating manganese dioxide and aluminum, aluminum displaces manganese from manganese dioxide to form aluminum oxide.

$3 {MnO}_{2} + 4 Al \to 3 Mn + 2 {Al}_{2} O_{3} + heat .$

We will understand in terms of oxidation-reduction reactions. Aluminum is a strong reducing agent. It should be noted that aluminum precedes manganese in its ease of oxidation or reduces aluminum more than manganese.

Therefore, aluminum is more reactive than manganese, which also explains why the first ionization energy of aluminum is lower than that of manganese. The lower the ionization energy, the more reactive the element.

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