When nitrobenzene is treated with ${Br}_{2}$ in presence of ${FeBr}_{3},$ the major product formed is m-bromonitrobenzene. Statement which is related to obtain the m-isomer is

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the intermediate carbonium ion formed after initial attack of Br+ at the meta position is least destabilized

the electron density on meta carbon is increased than that on ortho- and para-positions

loss of aromaticity when ${Br}^{+}$ attacks at the ortho and para positions and not at meta position

easier loss of $H^{+}$ to regain aromaticity from the meta position than from ortho and para positions.

answer is B.

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Detailed Solution

Electron withdrawing groups decrease, electron density in the o- and p-positions without effecting m-positions, thus in such cases meta positions will has relatively higher electron density than the ortho and para positions it is not increased due to $- {NO}_{2}$ group. The intermediate carbocation formed by the attack of an electrophile on nitrobenzene will have relatively unstable resonating structure in case of ortho and para position.

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