When NO and NO₂ are mixed, the following equilibria is established
$2 N O_{2 (g)} ⇌ N_{2} O_{4 (g)} K_{p} = 6.8 a t m$ and $N O_{(g)} + N O_{2 (g)} ⇌ N_{2} O_{3 (g)}$
In an experiment, when $N O$ and $N O_{2}$ are mixed in the molar ratio of $1 : 2$ , the final total pressure is $5.05 a t m$ and the partial pressure of $N_{2} O_{4}$ is $1.7 a t m$ , what is the partial pressure of NO in atm.

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 1.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

At equilibrium

$\begin{array}{l} 2 N O_{2 (g)} ⇌ N_{2} O_{4 (g)} K_{p} = 6.8 a t m ........ (i) \\ 2 p - 3.4 - x 1.7 a t m \\ N O_{(g)} + N O_{2 (g)} ⇌ N O_{23 (g)} ........... (i i) \\ P - x 2 p - x - 3.4 x \end{array}$

From equation (i) $6.8 = \frac{1.7}{p_{N O_{2}}^{2}}; ∴ P_{N O_{2}} = 0.5 a t m$
From equation (i) & (ii) $2 p - x - 3.4 = 0.5 = P_{N O_{2}}$
$∴$ Total $P = 5.05 = 0.5 + 1.7 + P$
$∴$ $P = 2.85 a t m$