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When octa-O-methyl D-cellobiose is hydrolysed by aqueous acid, two O-methylated glucose derivatives are formed:

One is tetramethyl derivative and the other is trimethyl derivative. Why is a single methyl substituent lost in this process?

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One methoxy group is lost by HOH₂C ß - elimination

One methoxy group is an ester and the others are all ethers

One methoxy group is a part of an acetal, the others are all ethers

One glucose is an α-methyl glycoside; the other is a ß-methyl glycoside

answer is C.

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One methoxy group is a part of an acetal, the others are all ethers.

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