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Q.

When one mole of manganese is burnt completely to form Mn3O4(s) at standard state conditions, the amount of heat liberated is (∆Hf of Mn3O4 = - 1388 kJ/mole)

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a

426.67kJ

b

576.67kJ

c

624.67kJ

d

462.67kJ

answer is B.

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Detailed Solution

3Mns+2O2g→Mn3O4s,    ΔH=-1388KJ/mole

For 3 mole Mn heat liberated is 1388KJ
1 mole Mn -------?

Heat liberated = 13883=462.67

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When one mole of manganese is burnt completely to form Mn3O4(s) at standard state conditions, the amount of heat liberated is (∆Hf of Mn3O4 = - 1388 kJ/mole)