When phosphate salt is heated with ammonium molybdate in presence of conc. ${\text{HNO}}_{\text{3}}$ , a precipitate is formed. Following are the steps involved

1.  ${\text{Na}}_{\text{3}}{\text{PO}}_{\text{4}}+{\left({\text{NH}}_4\right)}_2{\text{Mo\hspace{0.17em}O}}_4\to {{\text{(NH}}_4)}_3{\text{PO}}_{\text{4}}+{\text{Na}}_2{\text{Mo\hspace{0.17em}O}}_{\text{4}}$
2.  ${\text{Na}}_{\text{2}}{\text{Mo\hspace{0.17em}O}}_{\text{4}}+2{\text{HNO}}_{\text{3}}\to {\text{H}}_2{\text{MoO}}_4+{\text{2NaNO}}_3$
3. ${\text{H}}_{\text{2}}{\text{MoO}}_{\text{4}}\to {\text{\hspace{0.17em}\hspace{0.17em}MoO}}_3+{\text{H}}_2\text{O}$
4. ${{\text{(NH}}_{\text{4}}\text{)}}_{\text{3}}{\text{PO}}_{\text{4}}+12{\text{MoO}}_{\text{3}}+6{\text{H}}_{\text{2}}\text{O}\to {{\text{(NH}}_4)}_3{\text{PO}}_{\text{4}}\cdot 12{\text{MoO}}_{\text{3}}\cdot 6{\text{H}}_{\text{2}}\text{O}$

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