When photons of energy $\mathrm{hc}/\mathrm{\lambda }$ fall on a metal surface, photoelectrons are ejected from it. If the work function of the surface is ${\mathrm{hv}}_0$, then

maximum kinetic energy of the photoelectron is equal to $(\mathrm{hc}/\mathrm{\lambda })$

maximum kinetic energy of the electron is $\left[(\mathrm{hc}/\mathrm{\lambda })-{\mathrm{hv}}_0\right]$

minimum kinetic energy of the photoelectron is equal to $\mathrm{hc}/\mathrm{\lambda }$

minimum KE of the photoelectron is zero