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When S in the form of $S_{8}$ is heated at 900K, the initial pressure of 1 atmosphere falls by 29% at equilibrium. This is because of conversion of some $S_{8} to S_{2}$ . Find the $K_{p}$ for reaction $S_{8 (g)} \Leftrightarrow 4 S_{2 (g)}$

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$2.55 {atm}^{3}$

$5.25 {atm}^{3}$

$0.255 {atm}^{3}$

answer is A.

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Detailed Solution

${S_{8}}_{(g)} ⇌ 4 S_{2 (g)}$

1 atm 0

$\frac{1 - 29}{100} \frac{4 \times 29}{100}$

0.71 1.16

$K_{P} = \frac{{p_{S}}_{2}^{4}}{P_{S_{B}}} = \frac{{(1.16)}^{4}}{0.71} = 2.55$

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