When Sn is treated with conc. HNO₃

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it is converted into stannous nitrate.

it is converted into stannic nitrate.

it is converted into metastannic acid.

it becomes passive.

answer is C.

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Detailed Solution

Tin (Sn) forms metastannic acid, nitric oxide, and water when Sn reacts with concentrated nitric acid.

$Sn + 4 conc . {HNO}_{3} ⟶ \underset{metastannic acid}{H_{2} {SnO}_{3}} + 4 {NO}_{2} + H_{2} O$

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