When taken in an eudiometer tube operating at room temperature and pressure and subjected to complete reaction, in which of the following options the contraction in volume is greater than or equal to 30% of original volume

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10 ml of $C H_{4} (g)$ and 30 ml of $O_{2} (g)$

$C O (g) a n d O_{2} (g)$ Taken in molar ratio 2:1

$C H_{4} (g)$ and $O_{2} (g)$ taken in a molar ratio 1: 6

$N_{2} (g)$ and $H_{2} (g)$ taken in a molar ratio 3:1

answer is A, B.

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Detailed Solution

$A) C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g)$
$2 1$
$0 0 2$
$% c h a n g e i n m o l e = \frac{1}{3} \times 100$
$B) C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (1)$
$10 m l 30 m l$
Volume contraction $= 20 m l$
% change in volume $= \frac{20}{40} \times 100$
C) $N_{2} (g) + 3 H_{2} (g) \to 2 N H_{3} (g)$
$3 m o l 1 m o l$
$[3 - \frac{1}{4}] m o l L . R 2 / 3 m o l$
$% c h a n g e = \frac{\frac{2}{3}}{4} \times 100$
$D) C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (1)$
$1 m o l 6 m o l$
$L . R 4 m o l 1 m o l$
$% c h a n g e i n m o l = \frac{2}{7} \times 100$