When temperature of gas is $20^{0} C$ and pressure is changed from $P_{1} = 1.01 \times 10^{5} P a$ to $P_{2} = 1.165 \times 10^{5} P a$ and the volume changed by 10%.the bulk modulus is

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$1.55 \times 10^{5} P a$

$1.4 \times 10^{5} P a$

$0.115 \times 10^{5} P a$

$1.01 \times 10^{5} P a$

answer is A.

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Detailed Solution

$Δ P = P_{2} - P_{1} = 0.155 \times 10^{5} P a$

$\frac{Δ V}{V} = \frac{1}{10}$

$B = \frac{Δ P}{\frac{Δ V}{V}} = \frac{0.155 \times 10^{5} P a}{\frac{1}{10}} = 1.55 \times 10^{5} P a$

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