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When the angle of inclination of an inclined plane is θ , an object slides down with uniform velocity. If the same object is pushed up with an initial velocity u on the same inclined plane, it goes up the plane and stops at a certain distance on the plane. There after the body.

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Stays at rest on the inclined plane and will not side down.

Slides down the inclined plane and reaches the ground with velocity less than "u"

Slides down the inclined plane and reaches the ground with velocity "u"

Slides down the inclined plane and reaches the ground with velocity greater than "u"

answer is D.

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Detailed Solution

Since the body is sliding down the inclined surface with constant velocity.

mgsinθ = f= $μ_{k} m g \cos θ; μ_{k} = \tan θ$

In the second case , when the body stops , mgsinθ = f and the body will not have any tendency to slide down the inclined surface because here $μ_{k} = tanθ to slide μ_{s} has to be equal to tanθ$

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