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When the energy of the incident radiation is increased by 20% the kinetic energy of the photoelectrons emitted from a metal surface increased from 0.5 eV to 0.8 eV. The work function of the metal is

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1.0 eV

1.3 eV

1.5 eV

0.65 eV

answer is A.

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Detailed Solution

$E = h ν - φ$

$\Rightarrow 0.5 = h ν - ϕ . . . . . . (1)$

and, $0.8 = 1.2 h ν - ϕ . . . . . . . . (2)$

From equation $(1) \times 1.2 \Rightarrow 0.6 = 1.2 h ν - 1.2 ϕ$ ........(3)

By (3) - (2) gives

$ϕ = 1 e V$

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