When the hydrocarbon A undergoes combustion in the presence of air, it requires 9.5
equivalents of oxygen and produces 3 equivalents of water. What is the molecular formula
of A?

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$C_{9} H_{9}$

$C_{6} H_{6}$

$C_{8} H_{6}$

$C_{9} H_{6}$

answer is B.

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Detailed Solution

$\begin{array}{l} C_{x} H_{y} + (x + \frac{y}{4}) O_{2} \to {xCO}_{2} + \frac{y}{2} H_{2} O \\ 9.5 3 \\ x + \frac{y}{4} = 9.5 y = 6 \\ 4 x = 38 - 6 = 32 \\ x = \frac{32}{4} = 8 \end{array}$

$∴ H y d r o c o r b o n i s$ $C_{8} H_{6}$

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