When the key is switched on, a current flow around a circular loop in a plane perpendicular to the plane of the paper. As seen from positions A and B, the current flows anticlockwise and clockwise, respectively (in the plane of the paper and on the axis of the coil). The magnetic field lines point from B to A. The resultant magnet's north pole is close to the surface:

 

In the question, it is stated that the coil's current runs clockwise when viewed from point A and anticlockwise when viewed from point B, both of which are on the axis of the loop. 

According to the right-hand thumb rule. The field lines will therefore appear to move from B to A along the axis of the coil and from A to B outside the loop. Since the field lines of a magnet move from south to north inside the magnet and from north to south outside the magnet, we can imply that that the north pole of the magnetic field lines of the coil lies close to point A.