Q.

When the kinetics of the reaction, 2A+2B+C, were studied using the method of initial rates, the data in the table below were obtained.

  Trial[A]0molL1[B]0molL1

Initial Rate of Reaction

molL1s1

       10.0600.0403.6×104
       20.0600.0807.2×104
       30.0300.125.4×104

What is the rate law for the reaction?

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a

Rate=k[A]2[B]2

b

Rate=k[A][B¯]

c

Rate=k[A]2[B]

d

Rate=k[A][B]2

answer is A.

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Detailed Solution

In Exp 1 and 2 the concentration of A is unchanged, thus, the rate is doubled. So Order with respect to A is 1.

When the concentration of B in same exp. is doubled, then the rate is doubled. Here, order with respect to B is also 1. Thus,

Rate=k[A][B¯]

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