When the molecules $N_{2}, O_{2}, F_{2}$ are arranged in order of increasing bond strength, which order is correct?

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$N_{2,} F_{2,} O_{2}$

$O_{2}, N_{2}, F_{2}$

$F_{2}, O_{2}, N_{2}$

$N_{2}, O_{2}, F_{2}$

answer is D.

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Detailed Solution

Triple bonds connect the $N$ atoms in $N_{2}$ . $O_{2}$ contains two double-bonded $O$ atoms. Single bonds connect the molecules of $F_{2}$ and ${Cl}_{2}$ .
The bond energy will increase as the number of bonds between atoms increases. Because the atoms in $F_{2}$ are closer together and exhibit stronger repulsion, ${Cl}_{2}$ has a higher bond energy than $F_{2}$ . $F_{2}$ has a lower bond energy as a result.
∴ Bond enthalpies are as follows: $= N_{2} > O_{2} > F_{2}$