When the planet Jupiter is at a distance of 824.7 million km from the earth. Its angular diameter is measured to be 35.72`` of arc. The diameter of Jupiter is

Distance of Jupiter from the Earth, $\mathrm{D}=824.7\times {10}^6\mathrm{km}$

Angular diameter 35.72′′ = $35.72\times 4.874\times {10}^{-6}\mathrm{rad}$

Diameter of Jupiter = d 

Using the relation, 

θ = d/ D

d=θ x D =$824.7\times {10}^6\mathrm{km}\times 35.72\times 4.874\times {10}^{-6}\mathrm{rad}$

d = $1.429\times {10}^{5}km$