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When the pressure on a gas is decreased to 1/4 and the absolute temperature is increased four-fold the volume of the gas

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remains the same

Increases by 8 times

Increases by 16 times

decreases to 1/16

answer is A.

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Detailed Solution

$P_{1} = P P_{2} = \frac{P}{4}$

$t_{1} = t, t_{2} = 4 t$

$V_{1} = V, V_{2} = ?$

$\frac{P_{1} V_{1}}{t_{1}} = \frac{P_{2} V_{2}}{t_{2}}$

$\frac{PV}{t} = \frac{P / 4 \times V_{2}}{4 t}$

$V_{2} = 16 V$

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