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When the road is dry and coefficient of friction is $μ$ , the maximum speed of a car in a circular path is 10m/sec, If the road becomes wet and $μ^{|} = μ /2$ . What is the maximum speed permitted

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5 m/sec

10 m/sec

10 \sqrt{2} m/sec

5 \sqrt{2} m/sec

answer is D.

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Detailed Solution

v = \sqrt{μ gr}

$\frac{v_{2}}{v_{1}} = \sqrt{\frac{μ_{2}}{μ_{1}}} = \sqrt{\frac{1}{2}} \Rightarrow v_{2} = \frac{10}{\sqrt{2}} = 5 \sqrt{2} m/sec$

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