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When the state of a gas adiabatically changed from an equilibrium state A to another equilibrium state B an amount of work done on the stystem is 35 J. If the gas is taken from state A to B via process in which the net heat absorbed by the system is 12 cal, then the net work done by the system is (1 cal = 4.19 J)

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12.6 J

15.4 J

13.2 J

16.8 J

answer is B.

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Detailed Solution

(2) In the first-case adiabatic change,

$∆ Q = 0, ∆ W = - 35 J$

From 1st law of thermodynamics,

$∆ Q = ∆ U + ∆ W, o r 0 = ∆ U - 35 ∴ ∆ U = 35 J$

In the second case

$∆ Q = 12 c a l = 12 \times 4.2 J = 50.4 J ∆ W = ∆ Q - ∆ U = 50.4 - 35 = 15.4 J$

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