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When the voltage applied to an X -ray tube is increased from V₁ = 10 kV to V₂ = 20 kV, the
wavelength difference between the $K_{α}$ line and the short wavelength limit of the continuous X -ray spectrum increases by a factor 3. The atomic number of the element of which the tube anticathode is made will be

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answer is D.

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Detailed Solution

$λ_{α} - λ_{m}^{'} = 3 (λ_{α} - λ_{m})$

$∴ \frac{12375}{10.2 (Z - 1)^{2}} - \frac{12375}{20 \times 10^{3}} = 3 [\frac{12375}{10.2 (Z - 1)^{2}} - \frac{12375}{10 \times 10^{3}}]$

Solving, we get Z = 29

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