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Q.

When two bodies approach each other with the different speeds, the distance between them decreases by 120 m for every one minute. If they are moving in same direction, the distance between them increases by 90 m for very one minute. The speeds of the bodies are

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a

1.75 ms^–1and 0.25 ms^–1

b

3 ms^–1and 2 ms^-1

c

2 ms^–1and 0.5 ms^–1

d

2.5 ms^–1 and 0.5 ms^–1

answer is C.

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Detailed Solution

The relative velocity is vector subtraction

V₁+V₂ = 120/60 = 2 ; V₁ - V₂ = 90/60 = 1.5

$∴$ 2V₁ = 3.5 ⇒ V₁ = 3.5/2

V₁ = 1.75 ms^-1 ; Hence V₂ = 0.25 ms^-1

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When two bodies approach each other with the different speeds, the distance between them decreases by 120 m for every one minute. If they are moving in same direction, the distance between them increases by 90 m for very one minute. The speeds of the bodies are