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When two cohernt monochromatic light beams of amplitudes A and 4A are superimposed, the ratio between maximum and minimum intensities in the resultant beam is

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4 : 1

1 : 4

9 :25

25 : 9

answer is D.

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Detailed Solution

$\frac{I_{max}}{I_{min}} = {(\frac{A_{1} + A_{2}}{A_{1} - A_{2}})}^{2} = {(\frac{A + 4 A}{A - 4 A})}^{2} = \frac{25}{9}$

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