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When two identical batteries of internal resistance 1Ω each are connected in series across a resistor R, the rate of heat produced in R is J1. When the same batteries are connected in parallel across R, the rate is J2. If J1=2.25J2 then the value of R in Ω is

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detailed solution

4

P=i2R,i=nER+nr inseriesi=ER+rn inparallel 

Given that J1 = 2.25 J2 

on solving we get R=4Ω

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