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When two lenses of power -6D and +4 D are placed together, the combination acts as a

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convex lens of focal length = 10 cm

concave lens of focal length = 10 cm

convex lens of focal length = 50 cm

concave lens of focal length = 50 cm

answer is D.

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Detailed Solution

$P = P_{1} + P_{2} = (- 6 + 4) = - 2 D$
$P = \frac{1}{f} \Rightarrow f = \frac{1}{- 2} = - 0.5 m = - 50 cm$

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