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Q.

When two moles of an ideal gas Cp,m.=52R heated from 300 K to 600 K at constant pressure, the change in entropy of gas (68) is :

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a

5 R In 2

b

32R In 2

c

32R In 2

d

52R In 2

answer is C.

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Detailed Solution

Change in entropy can be given as,

ΔS=nCp in T2T1  (for constant pressure)

We have given that,

n=2 moles CP=52RT2=600KT1=300K

So,

ΔS=2×52R×ln 600300ΔS=5R ln 2

 


 

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