When two resistors of (600 $\pm$ 3) ohm and (300 $\pm$ 6) ohm are connected in parallel, value of the equivalent resistance is

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$200 ohm \pm 1.5 %$

$200 ohm \pm 9 %$

$200 ohm \pm 3.5 %$

200 ohm

answer is A.

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Detailed Solution

$\begin{array}{rcl} R_{1} & = & 600 \pm 3 Ω; R_{2} = 300 \pm 6 Ω \\ R_{P} & = & \frac{R_{1} R_{2}}{R_{1} + R_{2}} = 200 Ω \\ \frac{1}{R_{P}} & = & \frac{1}{R_{1}} + \frac{1}{R_{2}} \Rightarrow \frac{{ΔR}_{P}}{R_{P}^{2}} = \frac{{ΔR}_{1}}{R_{1}^{2}} + \frac{{ΔR}_{2}}{R_{2}^{2}} \\ {ΔR}_{P} & = & 200 \times 200 [\frac{3}{600 \times 600} + \frac{6}{300 \times 300}] \\ = & 4 [\frac{1}{12} + \frac{2}{3}] = 3 \\ \frac{{ΔR}_{P}}{R_{P}} % & = & \frac{3}{200} \times 100 = 1.5 % \\ ∴ The equivalent resistance & = & 200 \pm 1.5 % \end{array}$