Q.

When two resistors with resistance 5  and 10  are connected to 6 V emf battery, then the minimum current drawn from the circuit is


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a

0.4 A

b

2 A

c

5 A

d

None of the above 

answer is A.

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Detailed Solution

When two resistors with resistance 5 Ω and 10 Ω are connected to 6 V emf battery, then the minimum current drawn from the circuit is 0.4 A.
It is given that two resistors of resistances 5 Ω and 10 Ω are connected to 6 V emf battery.
According to the Ohm’s law, “the potential difference V across two terminals is directly proportional to the flow of current (I) across the circuit.” Mathematically,
V=IR or
I=VR
Where R is the resistance.
Hence, it can be observed that the current and resistance is inversely proportional to each other. It is known that when the resistors are connected in series then the value of resistance is maximum which in turn allows minimum current to flow through the circuit. The equivalent resistance is given by
RS=5+10
RS=15 Ω
Let Imin represent the minimum current flowing through the circuit. Now, from Ohm’s law, the minimum current in the circuit is equal to
Imin=VRS
On substituting the given values, we get the minimum current Imin as
Imin=615
 Imin=0.4 A
Hence, the minimum current through the circuit is 0.4 A.
 
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