When two waves of nearly equal frequencies superimpose them. The frequency of combined wave is 'f1', that of the amplitude is 'f2' and the beat frequency is 'f3'. Arrange them in increasing order of frequency.

y1=Asin2πf4ty2=Asin2πf5tynet=2Acos2πf4-f52tsinπ2f4+f52tGiven, f1=f4+f52 ; f2=f4-f52 ; f3=f4-f5Thus, f2 < f3 < f1

When two waves of nearly equal frequencies superimpose them. The frequency of combined wave is 'f1', that of the amplitude is 'f2' and the beat frequency is 'f3'. Arrange them in increasing order of frequency.

y1=Asin2πf4ty2=Asin2πf5tynet=2Acos2πf4-f52tsinπ2f4+f52tGiven, f1=f4+f52 ; f2=f4-f52 ; f3=f4-f5Thus, f2 < f3 < f1

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When two waves of nearly equal frequencies superimpose them. The frequency of combined wave is 'f₁', that of the amplitude is 'f₂' and the beat frequency is 'f₃'. Arrange them in increasing order of frequency.

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f₃ < f₂ < f₁

f₁ < f₃ < f₂

f₂ < f₃ < f₁

f₁ < f₂ < f₃

answer is C.

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Detailed Solution

$y_{1} = Asin 2 {πf}_{4} t$

$y_{2} = Asin 2 {πf}_{5} t$

$y_{net} = 2 Acos 2 π (\frac{f_{4} - f_{5}}{2}) tsinπ 2 (\frac{f_{4} + f_{5}}{2}) t$

Given, $f_{1} = \frac{f_{4} + f_{5}}{2}$ ; $f_{2} = \frac{f_{4} - f_{5}}{2}$ ; $f_{3} = f_{4} - f_{5}$

Thus, f₂ < f₃ < f₁

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When two waves of nearly equal frequencies superimpose them. The frequency of combined wave is 'f1', that of the amplitude is 'f2' and the beat frequency is 'f3'. Arrange them in increasing order of frequency.

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When two waves of nearly equal frequencies superimpose them. The frequency of combined wave is 'f₁', that of the amplitude is 'f₂' and the beat frequency is 'f₃'. Arrange them in increasing order of frequency.