When two waves of nearly equal frequencies superimpose them. The frequency of combined wave is 'f₁', that of the amplitude is 'f₂' and the beat frequency is 'f₃'. Arrange them in increasing order of frequency.

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f₃ < f₂ < f₁

f₁ < f₃ < f₂

f₂ < f₃ < f₁

f₁ < f₂ < f₃

answer is C.

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Detailed Solution

$y_{1} = Asin 2 {πf}_{4} t$

$y_{2} = Asin 2 {πf}_{5} t$

$y_{net} = 2 Acos 2 π (\frac{f_{4} - f_{5}}{2}) tsinπ 2 (\frac{f_{4} + f_{5}}{2}) t$

Given, $f_{1} = \frac{f_{4} + f_{5}}{2}$ ; $f_{2} = \frac{f_{4} - f_{5}}{2}$ ; $f_{3} = f_{4} - f_{5}$

Thus, f₂ < f₃ < f₁

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