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Q.

When U235 undergoes fission, 0.1% of the original mass is converted into energy. The energy released by an atom bomb with 10kg of U235 is

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a

20 MeV

b

9×1014J

c

2 MeV

d

9×1017J

answer is D.

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Detailed Solution

ΔM=0.1%M= 103(10kg)=102kg

Energy released = ΔMC2

= 102(3×108)2= 9×1014J

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