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When ultraviolet light of wavelength 100 nm is incident upon silver plate, a potential of 7.7 V is required to stop the photoelectrons from reaching the collector plate. How much potential will be required to stop the photoelectrons when light of wavelength 200 nm is incident upon silver?

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1.5 V

3.85 V

2.35 V

15.4 V

answer is A.

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Detailed Solution

Here, $λ_{1} = \frac{12375}{E_{1} (in eV)} \overset{0}{A} = 1000 \overset{0}{A}$

$∴$ $E_{1} = 12.375 eV$

Similarly, $E_{2} (eV) = \frac{12375}{λ_{2} (in \overset{0}{A})} eV = \frac{12375}{2000} = 6.1875 eV$

Now, $E_{1} - W_{0} = e V_{1}$

and $E_{2} - W_{0} = e V_{2}$

Hence, $12.375 - W_{0} = 7.7$ $\Rightarrow W_{0} = 4.675 eV$

and $6.1875 - W_{0} = e V_{2}$

Solving, we get $V_{2} ≃ 1.5 V$

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