When unknown resistance and a resistance of 5Ω are used in left and right gaps of meter bridge the balance point is 50 cm. The balancing point if 5Ω resistance is now connected in series to the resistor in right gap

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20 cm

60 cm

40 cm

33.3 cm

answer is B.

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Detailed Solution

$\begin{array}{l} \frac{x}{5} = \frac{l}{100 - l}; \frac{x}{5} = \frac{50}{100 - 50}; x = 5 Ω \\ \frac{5}{5 + 5} = \frac{l^{'}}{100 - l^{'}}; solving, l^{'} = \frac{100}{3} = 33 .3 cm \end{array}$

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