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Q.

When voltage applied to an X-ray tube increases from 10kV to  20kV  the wavelength difference between the kα  line and the short wave cut-off of continuous X-ray spectrum increases by a factor of 3.0. Identify the  target element. Take 43R1200 A0  where R is Rydberg’s constant and  hc=12.4keVA0

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a

Z =29

b

Z = 38

c

Z = 44

d

Z = 22 

answer is A.

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Detailed Solution

λk=43R(Z1)2=1200(Z1)2Å 
λc=12.4 V  where  V  is in  kV
1200(Z1)212.4V=Δλ 
1200(Z1)212.410=Δλ ...(i)
and  1200(Z1)212.420=3Δλ ....(ii) 
Eliminating Δλ between (i) and (ii) we get Z=28.829

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