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When (X) moles of boron is fused with (Y) moles of NaOH at STP 67.2 lits of dry H₂ gas is liberated. Ratio between X and Y is

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1:6

2:3

3:1

2:6

answer is D.

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Detailed Solution

2B + 6NaOH $\overset{fuse}{\to}$ 2Na₃BO₃ + 3H₂

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