When $10 m L$ of an aqueous solution of ${F e}^{2 +}$ ions was titrated in the presence of dil $H_{2} {S O}_{4}$ using diphenylamine indicator, $15 m L$ of $0.02 M$ solution $K_{2} {C r}_{2} O_{7}$ was required to get the end point. The molarity of the solution containing ${F e}^{2 +}$ ions is $x \times 10^{- 2} M$ . The value of $x$ is ___. (Nearest integer)

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answer is 18.

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Detailed Solution

${Fe}^{+ 2} + {Cr}_{2} O_{7}^{- 2} \to {Fe}^{+ 3} + 2 {Cr}^{+ 3}$
Milli-equivalents of ${F e}^{2 +} =$ milli-equivalents of $K_{2} {C r}_{2} O_{7}$

$M \times 10 \times 1 = 0.02 \times 15 \times 6$

$M = 0.18 = 18 \times 10^{- 2} M$

Hence the correct answer is 18.

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