When $10 m L$ of an aqueous solution of ${K M n O}_{4}$ was titrated in acidic medium, equal volume of $0.1 M$ of an aqueous solution of ferrous sulphate was required for complete discharge of colour. The strength of ${K M n O}_{4}$ in grams per litre is ____ $- 10^{- 2}$ . (Nearest integer)
[Atomic mass of $K = 39, M n = 55, O = 16$ ]

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 3.16.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Let molarity of ${K M n O}_{4} = x$

${K \overset{+ 7}{M n} O}_{4} + {\overset{+ 2}{F e} S O}_{4} \to {\overset{+ 3}{F e}}_{2} {({S O}_{4})}_{3} + {M n}^{2 +}$

(Equivalents of ${K M n O}_{4}$ reacted $) = ($ Equivalents of ${F e S O}_{4}$ reacted)

No. of equivalents=VM(n-factor)

$\Rightarrow (5 \times x \times 10 m l) = 1 \times 0.1 \times 10 m l \Rightarrow x = 0.02 M$

Molar mass of ${K M n O}_{4} = 158 g m / m o l$

$\Rightarrow S t r e n g t h = (x \times 158) = 3.16 g / ℓ$

Hence the correct answer is 3.16.

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE