$\text{ When }1\text{ mole of benzene is mixed with }1\text{ mole of toluene The vapour will contain: (Given : vapour pressure of benzene }=12.8\mathrm{kPa}\text{ and vapour pressure of }$$\mathrm{toluene} =3.85\mathrm{kPa}\text{. }$

$\text{ equal amount of benzene and toluene as it forms an ideal solution }$

$\text{ unequal amount of benzene and toluene as it forms a non ideal solution }$

$\text{ higher percentage of benzene }$

$\text{ higher percentage of toluene }$