When $1$ mole of $PbS$ reacts completely with $H_{2} O_{2}$

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$H_{2}$ is liberated.

$O_{2}$ is liberated.

$4$ moles of $H_{2} O_{2}$ consumed.

Sulphur is converted to Sulphate.

answer is C.

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Detailed Solution

The equation is :-

$PbS + 4 H_{2} O_{2} \to {PbSO}_{4} + 4 H_{2} O$

Lead $(II)$ sulfide react with hydrogen peroxide to produce lead $(II)$ sulfate and water. So, the correct answer is $4$ moles of $H_{2} O_{2}$ consumed.

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