When $50{\mathrm{cm}}^3$ of 0.2N  $H_2{\mathrm{SO}}_4$ is mixed with $50{\mathrm{cm}}^3$ of 1N KOH, the heat liberated is

${\mathrm{H}}_2{\mathrm{SO}}_4 + 2\mathrm{KOH} \to {\mathrm{K}}_2{\mathrm{SO}}_4 + 2{\mathrm{H}}_2\mathrm{O}$

0.01 eq             0.05eq                                     0.01eq

one equivalent of water formed will liberate heat of neutralisation 57300 joules

therefore the heat liberated for 0.01 equivalent is 573 joules .