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When $7.1 g m N a_{2} S O_{4}$ (molecular mass $142$ ) dissolves in $100 m l$ $H_{2} O,$ the molarity of the solution is

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$2.0 M$

$0.05 M$

$1.0 M$

$0.5 M$

answer is C.

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Detailed Solution

Molarity $= \frac{w \times 1000}{mol . wt . \times Volume (ml) .} = \frac{7.1 \times 1000}{142 \times 100} = 0.5 M .$

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