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When a sound wave of wavelength ' $λ$ ' is propagating in a medium, the maximum velocity of the particle is equal to the velocity of propagation. The amplitude of waves is

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λ

$\frac{λ}{2}$

$\frac{λ}{2 π}$

$\frac{λ}{4 π}$

answer is C.

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Detailed Solution

$u_{{wave}_{}} = V_{\max} = Aω = nλ$

$A = \frac{nλ}{ω} = \frac{nλ}{2 πn} = \frac{λ}{2 π}$

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