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When ${CH}_{3} Cl$ undergoes homolytic bond–fission:

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none of the above takes place

both of the above statements are correct

hybridization changes from $s p^{3}$ to $s p^{2}$

carbon undergoes a geometric change from tetrahedral to planar

answer is C.

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Detailed Solution

sp³ carbon will cleave and changes to sp² carbon. Formation of carbocation will occur.

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