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When ${CO}_{2}$ is bubbled through a solution of bariur peroxide in water.

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$O_{2}$ is released

Carbonic acid is formed

$H_{2} O_{2}$ is formed

No reaction occurs

answer is C.

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Detailed Solution

When ${CO}_{2}$ is bubbled through a cold pasty solution of barium peroxide in water $H_{2} O_{2}$ is obtained.

${BaO}_{2} + {CO}_{2} + H_{2} O \to {BaCO}_{3} + H_{2} O_{2}$

Barium carbonate being insoluble is filtered off This is known as Merck's process.

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