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When ${CuSO}_{4}$ solution is added to $K_{4} [Fe (CN)_{6}],$ the formula of the product formed is

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${Cu}_{2} Fe (CN)_{6}$

$K C N$

$C u (C N)_{3}$

$Cu (CN)_{2}$

answer is A.

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Detailed Solution

$2 {CuSO}_{4} + K_{4} (Fe (CN)_{6}] \to {Cu}_{2} [Fe (CN)_{6}] + 2 K_{2} {SO}_{4} .$

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