When ${\mathrm{E}}_{{\mathrm{Ag}}^{+}|\mathrm{Ag}}^0=0.80\text{ volt }\mathrm{\&}{\mathrm{E}}_{{\mathrm{Zn}}^{+2}|\mathrm{Zn}}^0=-0.76$volt, which of the following is correct? 

E^o_Ag⁺/Ag=0.8 volt  E ^o_{Zn ²⁺/Zn}​=−0.76 volt ,

 then Ag⁺ can be reduced by H₂​   Because H₂​ has lesser reduction potential