When $I_{2}$ is passed through KCl, KF, KBr :

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${Cl}_{2}$ and ${Br}_{2}$ are evolved

${Cl}_{2}$ is evolved

${Cl}_{2}, F_{2}$ and ${Br}_{2}$ are evolved

none of the above

answer is D.

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Detailed Solution

Because $I_{2}$ is the weakest oxidising agent, it cannot replace ${Br}_{2}, {Cl}_{2}, or F_{2}$ in $KBr, KCl$ or $KF$ . Hence When $I_{2}$ is passed through KCl, KF, KB no reaction occurs.

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